Research Article, Res Rep Math Vol: 1 Issue: 1

# A Simpler Proof of the Characterization of Quadric CMC Hypersurfaces in Sn+1

**Aquino CP ^{1*} and De Lima HF^{2}**

^{1}Department of Mathematics, Universidade Federal do Piaui, Teresina, Brazil

^{2}Department of Mathematics, Universidade Federal de Campina Grande, Campina Grande, Paraiba, Brazil

***Corresponding Author :** **Aquino CP**

Department of Mathematics, Universidade Federal do Piaui, Teresina, Brazil

**Tel:** (86) 3215-5525

**E-mail:** [email protected]

**Received:** August 10, 2017 **Accepted:** September 01, 2017 **Published:** September 07, 2017

**Citation:** Aquino CP, De Lima HF (2017) A Simpler Proof of the Characterization of Quadric CMC Hypersurfaces in S^{n+1}. Res Rep Math 1:1.

## Abstract

In this short article, we present a new and simpler proof of a characterization of the quadric constant mean curvature hypersurfaces of the Euclidean sphere S^{n+1}, originally due to Alias, Brasil and Perdomo.

### Keywords: Euclidean sphere; Constant mean curvature hypersurfaces; Support functions; Totally umbilical hypersurfaces; Clifford torus

## Introduction

In 2008, Alias, Brasil and Perdomo studied complete hypersurfaces immersed in the unit Euclidean sphere , whose height and angle functions with respect to a fixed nonzero vector of the Euclidean space are linearly related. Let us recall that, for a fixed arbitrary vector the height and the angle functions naturally attached to a hypersurface endowed with an orientation ν are defined, respectively, by and In this setting, they showed the following characterization result concerning the quadric constant mean curvature hypersurfaces of S^{n+1} [1,2]:

**Theorem 1**

Let be a complete hypersurface immersed in S^{n+1} with constant mean curvature. l_{a}=λ f_{a} for some non-zero vector and some real number λ, then Σ^{n} is either a totally umbilical hypersurface or a Clifford torus , for some k = 0; 1;..; n and some k=0,1,…,n and ρ>0.

Later on, working with a different approach of that used in [2], the first and second authors characterized the totally umbilical and the hyperbolic cylinders of the hyperbolic space Hn+1as the only complete hypersurfaces with constant mean curvature and whose support functions with respect to a fixed nonzero vector a of the Lorentz- Minkowski space are linearly related (see Theorem 4:1 of [3,4], for the case that a is either space like or time like, and Theorem 4:2 of [5], for the case that a is a nonzero null vector). In this short article, our purpose is just to use a similar approach of that in [4,5] in order to present a new and more simple proof of Theorem 1 (cf. Section 3). For this, in Section 2 we recall some preliminaries facts concerning hypersurfaces immersed in S^{n+1}.

**Preliminaries**

Let be an orientable hypersurface immersed in the Euclidean sphere. We will denote by A the Weingarten operator of Σ^{n} with respect to a globally defined unit normal vector ν.

In order to set up the notation, let us represent by ∇^{0} , ∇and ∇ the Levi-Civita connections of , S^{n+1} and Σ^{n} respectively. Then the Gauss and Weingarten formulas for Σ^{n} in S^{n+1} are given, respectively, by

and

for all tangent vector fields

In what follows, we will work with the first three symmetric elementary functions of the principal curvatures λ_{1},… λ_{n} of ψ, namely:

where i, j, k ∈ {1,…, n}.

As before, for a fixed arbitrary vector a let us consider the height and the angle functions naturally attached to which are defined, respectively, by and . A direct computation allows us to conclude that the gradient of such functions are given by and , where a^{Τ} is the orthogonal projection of a onto the tangent bundle Τ Σ , that is,

Taking into account that and using Gauss and Weingarten formulas, we obtain for all . We use this previous identity jointly with Codazzi equation to deduce that

For all that Thus according to [6] (see also [3]), it follows from the last two identities that

(2.1)

(2.2)

where H = (1/n) S_{1} is the mean curvature function of Σ^{n}

For what follows, it is convenient to consider the so-called Newton transformation

P_{1}= S_{1}-A

where I is the identity operator. Naturally associated with the Newton transformation P1, we have the Cheng-Yau’s square operator [7], which is the second order linear di erential operator given by

(2.4)

Here stands for the self-adjoint linear operator metrically equivalent to the hessian of h, and it is given by

For all X, Y∈ x (Σ) .

Based on Reilly’s seminal paper [8-10], Rosenberg [6] showed the following idenfitities related to the action of on the functions l_{a} and f_{a}:

(2.5)

And

(2.6)

To close this section, we quote a suitable Simons-type formula which can be found in [1] or [11].

(2.7)

**Proof of Theorem**

Now, we are in position to proceed with our alternative proof of Theorem 1.1. If λ=0 then l_{a}= λf_{a}=0, that is

for all and, consequently, Σ^{n} is a totally umbilical sphere of S^{n+1}.

So, let us assume that λ≠0. We have Δla_{=}λΔfa_{ a}nd using the fact that H is constant, from (2.1) and (2.2) we conclude that

Or equivalently,

Hence, we get that

(3.1)

By (3.1), we obtain

Thus,

(3.2)

We define a function

by

Suppose that h(p_{0})≠0 for some p_{0} ∈ Σ^{n} Since h is smooth, there exists a neighbourhood u of p_{0} in Σ^{n} in which h(p)≠0 all p∈ u From (3.2) we conclude that l_{a}=0 in u and, hence f_{a}=0 in u. since λ≠0. we arrive at a contradiction because in Σ^{n} we have

Therefore, h = 0 on Σ^{n}, that is,

(3.3)

Consequently, S_{2} is constant on Σ^{n} . Repeating the previous argument for the operator L_{1} and using the fact that S_{2} is constant, we also obtain that

(3.4)

We observe that the above equation shows that S_{3} is also constant on Σ^{n} . We also note that this argument shows, in fact, that S_{r} is a constant function on Σ^{n} for all 2≤r≤n. From (2.7) we get

More precisely,

(3.5)

We observe that if H=0, then S1=0 and, consequently, |A|^{2}=−2s_{2} From (3.3), we have 2S_{2} =−n and |A|_{2} = n. Therefore, since

We have that and, hence, from Theorem 4 of [9], we conclude that Σ^{n} must be a Clifford torus

, for some k=0,1,…,n and some ρ>0.

Now, suppose that H≠0 By equation (3.4) we get

that is,

(3.7)

From equation (3.5) we have

(3.8)

Furthermore, from a straightforward computation we can verify that

(3.9)

Hence, if S_{2} = 0 we obtain of (3.9) that consequently, |∇A|^{2} =0 and, since Σ^{n} is complete, it follows once more from Theorem 4 of [9] that Σ^{n} must be a Clifford torus.

If S_{2}≠0 then implies

(3.10)

We note that (3.10) and (3.9) imply and, hence, repeating the previous argument we also get that Σ^{n} is a Clifford torus. Therefore, we conclude the proof of Theorem 1.

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